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0=0.2x^2+5
We move all terms to the left:
0-(0.2x^2+5)=0
We add all the numbers together, and all the variables
-(0.2x^2+5)=0
We get rid of parentheses
-0.2x^2-5=0
a = -0.2; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·(-0.2)·(-5)
Δ = -4
Delta is less than zero, so there is no solution for the equation
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